Factorissing -9/16n^2 is (3/4n)(3/4n) and not (9/16n)(9/16n) Therefore, when the first step is wrong, the final answer is also incorrect.
when factorising -9/16n^2 the result should be -(3/4n)(3/4n)as a result the rest of the problem is wrong.
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remember when u square root u need to square root like what u did for 1/4m^2. Similarly, u have to make 9/16n^2 to (3/4n)(3/4n) too.
(9/16 n)(9/16 n) is not equal to (9/16 n^2). Instead, (3/4n)(3/4n)=9/16n^2 thus, the final answer is also wrong.
9/16 is not squared, thus, this is wrong. The student did not square 9/16 as he did with 1/4, thus, this is wrong.
9/16n ² ≠ (9/16n x 9/16n)9/16n ² = (3/4n x 3/4n)
9/16n^2 is not (9/12n), but (3/4n), so it should be -(3/4n)(3/4n)
9/16 has not been squared, resulting in a wrong answer.
The student factories wrongly for -9/16n^2, it should be (3/4n)(3/4n), not (9/16n)(9/16n).
9/16 nˆ2 does no equal to (9/16 n)(9/16 n) but instead (3/4n)(3/4n).
-9/16n2 is not -(9/16n)(9/16n)1/4 m2 - 9/16 n2= (1/2m)(1/2m) - (3/4n)(3/4n)= (1/2m-3/4n)(1/2m+3/4n)
for the 2nd statement it should be (3/4)2 instead of (9/16)2so the rest of the statement is wrong
Though I'm quite convinced this is my handwriting, I'm ready to redo the question. Squareroot 9/16n^2 is not 9/16n*2 , thus the rest of the solution is wrong.
The student did not find the square root of 9/16 n^2, and therefore got the answer wrong. It should look like this: (1/4 m^2)-(9/16 n^2)= (1/2 m)^2-(3/4 n)^2= (1/2 m-3/4 n)(1/2 m+3/4 n)
(9/16n)(9/16n) is not equal to 9/16n^2. It should be (3/4n)(3/4n) instead. Thus, the answer would be (1/2m+3/4n)(1/2m-3/4n).